Am I √(1+tan²c)?

Comments (15)

Not only is it mathematically incorrect, it's incorrect in general.

𖀐 𝐚𝐦𝐲𝐲𝐲 𖀐

sec(c)

I know.

it is not an imaginary number. (1+tan^2(c)^1/2 is 1.19580389338. inputting c, or the speed of light in m/s, that is what I got.

π“œπ“ͺ𝓭𝓲

AYHHAUYDH

You are deeply disturbed.

The Lion Cub (alt)

it is not an imaginary number. (1+tan^2(c)^1/2 is 1.19580389338. inputting c, or the speed of light in m/s, that is what I got.

in rads